Question

can anyone pls solve this sum its urgent no irrelevant answers chapter is differentiation class 11 please pls ​

Answer 1

Answer:

The correct answer is number 4

Step-by-step explanation:

Hope it helps you

Answer 2

Answer:

$\frac{ d}{dx} ( \frac{1}{3 {x}^{3} + 2} ) \\ = \frac{ - 1}{ {(3 {x}^{3} + 2)}^{2} } \\ \\ on \: \: substituting, \\ x = - 1 \\ \\ \frac{ - 1}{ {(3 {( - 1)}^{3} + 2) }^{2} } \\ = \frac{ - 1}{ { (- 1)}^{2} } \\ = - 1$

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Your Answer:

Option (d) None