Can anyone pls tell the answer?...
Question in this picture below
20 points awarded
Attachments:
Answers
Answered by
0
Since, ∆ABC is an equilateral triangle.
Therefore , AB=BC=CA
Let AB=BC=CA=a
Construction-
Join OB,OA & OC
Now,
Ar(ABC)=√3/4 a^2. (Area of an equilateral ∆
is calculated by the
formula (√3/4 a^2)
Ar(AOB+AOC+BOC) = √3/4 a^2
1/2(AB×OX+AC×OY+BC×OZ)=√3/4 a^2
7a+10a+12a=√3 × 2/4 a^2
29a=√3/2 a^2
a=58/√3
Therefore, Area of ∆ABC=√3/4 (58/√3)^2
=841/√3 cm^2
I hope my solution is correct!
Therefore , AB=BC=CA
Let AB=BC=CA=a
Construction-
Join OB,OA & OC
Now,
Ar(ABC)=√3/4 a^2. (Area of an equilateral ∆
is calculated by the
formula (√3/4 a^2)
Ar(AOB+AOC+BOC) = √3/4 a^2
1/2(AB×OX+AC×OY+BC×OZ)=√3/4 a^2
7a+10a+12a=√3 × 2/4 a^2
29a=√3/2 a^2
a=58/√3
Therefore, Area of ∆ABC=√3/4 (58/√3)^2
=841/√3 cm^2
I hope my solution is correct!
Diyarawat08:
sorry i forgot to attach the picture of the figure. Let me tell you that point O is that point from which perpendiculars are drawn
Answered by
3
Answer:
Thnx for free Pointssssss ☺️✌️...m
Similar questions