Question

Can anyone plsz help me out with q. No. 57,:59.....plsz it's today's cucet question paper. It's basic but I don't remember... Plsz help me out... ​

Answer 1

Answer:

Explanation:

the heat of neutralisation given is 57 KJ(per mol). In the given reaction HNO3 reacts with NaOH in the ratio of 1mole:1mole. This implies that only 0.2 mol of the strong base and strong acid will react and which will lead to 0.2*57 KJ of heat = 11.4 KJ of heat being released. the excess 0.3 mol of HNO3 need not be considered as it is excess and it does not contribute towards the heat of neutralisation.