Question

Can anyone plz answer all the mcq's given in the attachment

Answer 1

Answer:

3.d

4.c

5.a

6.c

7.b

8.d

9.c

10.a

11.b

12.d

13.a

14.c

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Answer 2

Answer:

Step-by-step explanation:

3= c              (it is because if you would solve lhs then u will get 2x^2 which will cancel from rhs therefore highest degree is 1 now so not at all quadratic)

4 = b          (just put x as three and equate it to 0)

5 = c           (we know that sum of roots is -b/a  so it is -(-6)/1  =  6)

6 = c         (product of roots is -c/a  therefore k-10 = -2   therefore k= 8)

               {remember to shift 10 to LHS}

7  = b        (just putx as 2 and then equate it to 0)

8  = c    (now u know that sum of roots is -b/a  and product is c/a )

             (so -b/a = 12   and c/a = 18    therefore ratio is 2:3)

9 = b                  (apply the formula$(-b+- \sqrt{(b^{2} -4ac) )/2a$    /2a is not under root)

10 = d                   (apply the above formula where a is coefficient of x²

                              b is coefficient of x and c is constant term)

11 = b        (just simply put the values from the options )

12 = d

13 = a       [for all these 12 , 13 , 14 simplify and apply the formula]

14 = c

 

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