can anyone plz answer this
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Answered by
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X^2. -2x+1=0
(x-1)^2=0
x=1
so this curve cuts X axis at (1,0)
so slope=(0-1)/(1-0)=-1
hope it helps.... mark brainliest if u are satisfied
(x-1)^2=0
x=1
so this curve cuts X axis at (1,0)
so slope=(0-1)/(1-0)=-1
hope it helps.... mark brainliest if u are satisfied
Answered by
1
when a line touches X-axis, Y-axis become 0
show, let line touches X-axis at (x, 0)
line x^2 -2x + 1 ...............(i)
x^2 -x -x + 1
x(x-1) -1(x-1)
(x-1) (x-1)
x = 1
so, the coordinate is (1,0)
show, let line touches X-axis at (x, 0)
line x^2 -2x + 1 ...............(i)
x^2 -x -x + 1
x(x-1) -1(x-1)
(x-1) (x-1)
x = 1
so, the coordinate is (1,0)
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