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According to me angle PAC = 90° because the tangent at any point of a circle is perpendicular to the radius through the point of contact
manaswini27g:
Angle abc will be equal to 90 degree by finding through sum of triangle
we need to find angle pca
PCA
Angle B C Q = angle BAC (angles in alternate segment)..... Similarly angle ACP = angle abc
Therefore PCQ is equal to sum of angle A C P + a c b + b c q which is equal to 60 + 90 + 30 which is equal to 180
you are completely wrong
According to you Angle PCO is 90
Yes u are right I also had a doubt
i have answered
Thanks
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