Question

Can Anyone plz help me !!!!

ABCD is a cyclic quadrilateral find the angles of the cyclic quadrilateral .​

Answer 1

Answer:

Step-by-step explanation:

In cyclic quad two opp sides are equal

As per que

Angle B=angleD

And

Angle A=angle C

3y-5=-7x+5

3y-7x=12....eq1

And

4y+20=-4x

4y+4x=-20... eq 2

Hope it helps u now u can solve by substitution or elimination method

Answer 2

Opposite sides are supplementary..

sooo
first...
$3y - 5 + - 7x + 5 = 180 \\ 3y - 7x = 180$
Eq----------1

second..

$4y + 20 + - 4x = 180 \\ 4y - 4x = 160$

Eq-----------2

solving the linear equations...

we get value of x and y