Can anyone plz help me to solve 38th question??plzzz its urgent
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it's not clear can you upload clear pic
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Answer:
The external surface area of the object is
CSA of frustum+CSA of hemisphere
=pie*l(r1+r2) +2pie(r²)
Step-by-step explanation:
pie[l(r1+r2)+2(r²) {l=underroot h²+(r1-r2)²}
&l=6.70
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