India Languages, asked by ljaya3807, 7 months ago

can anyone plzz answer to that question its telugu language plzzz answer i will mark you as brainlist after uh answer so plzzz answer plzzz​

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Answered by arhanashraf2006
0

Answer:

Given:

x = 3 and 5

\begin{gathered}\textsf{Putting \: the \: values \: of \: x \: in \:2x - y - 4 = 0 } \\ \\ \text{Putting \: x = 3}\end{gathered}

Putting the values of x in 2x - y - 4 = 0

Putting x = 3

2x – y – 4 = 0

arrowarrow 2×3 – y – 4 = 0

arrowarrow 6 – y – 4 = 0

arrowarrow –y = –2

arrowarrow y = 2

\boxed{ \textbf{y = 2}}

y = 2

\text{Putting \: x = 5}Putting x = 5

2x – y – 4 = 0

arrowarrow 2×5 – y – 4 = 0

arrowarrow 10 – y – 4 = 0

arrowarrow –y = –6

arrowarrow y = 6

\boxed{ \textbf{y = 6}}

y = 6

\text{area \: of \: formed \: quadrilateral}area of formed quadrilateral

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ABCD is a square \text{as shown in graph...}as shown in graph...

Area of square = (side)²

arrowarrow A = 2 × 2

arrowarrow A = 4 cm²

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Area of triangle = 1/2 × b × h

arrowarrow A = 1/2 × 2 × 4

arrowarrow A = 4 cm²

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Area of quadrilateral = Sum of area of square and triangle .

arrowarrow A = 4 cm² + 4 cm²

arrowarrow A = 8 cm²

\boxed{ \text{Area of quadrilateral = 8 sq. cm}}

Area of quadrilateral = 8 sq. cm

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