Can anyone plzz help me out with dis question...!!
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for first
in △ ADB AND △ BFE
∠ B = ∠ B ...common angle
∠ FEB = ∠ DAB ..... corresponding ∠
therfore
△ ADB AND △ BFE are similar.....AA TEST
now their sides are automatically similar
AD/EF=AB/EB....1
NOW AE / EB = 1/2
SO BY componendo
AE+EB/EB=1+2/2
AB/EB=3/2
from 1
AD/EF=3/2
in △ ADB AND △ BFE
∠ B = ∠ B ...common angle
∠ FEB = ∠ DAB ..... corresponding ∠
therfore
△ ADB AND △ BFE are similar.....AA TEST
now their sides are automatically similar
AD/EF=AB/EB....1
NOW AE / EB = 1/2
SO BY componendo
AE+EB/EB=1+2/2
AB/EB=3/2
from 1
AD/EF=3/2
Diaclya:
Plz answer d second one right now... I have my exam times
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