Question

can anyone say Sum of
Interior
Angles for

Pentagon
Decagon
Heptagon
12- gon
20-gon

Answer 1

Step-by-step explanation:

YEAH OFFCOURSE

PENTAGON = 5 SIDE

                    = A

                   =  1/4 SQUAREROOT 5 (5+2 SQUAREROOT 5 )A^2

Answer 2

Hey Friend , we have studied a formula in class 8 by which we can find the sum of interior angles of a regular shape that is ( n - 2 ) × 180 . Here "n" is number of sides the shape have .

Now ,

Sum of interior angles of Pentagon :-

( 5 - 2 ) × 180

3 × 180 = 540°

Sum of interior angles of Decagon :-

( 10 - 2 ) × 180

8 × 180 = 1440°

Sum of interior angles of Heptagon :-

( 7 - 2 ) × 180

5 × 180 = 900°

Sum of interior angles of 12 - gon:-

( 12 - 2 ) × 180

10 × 180 = 1800°

Sum of Interior angles of 20 - gon :-

( 20 - 2 ) × 180

18 × 180 = 3240° .

Hope , It helps you Dost !

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