Question

can anyone say who is this​

Answer 1

Let's solve your equation step-by-step.

$\sf \frac{x}{2} -\frac{1}{4}=\frac{x}{3}+\frac{1}{2}$

Step 1: Simplify both sides of the equation.

$\sf \frac{1}{2}x -\frac{1}{4}=\frac{1}{3}x+\frac{1}{2}$

Step 2: Subtract $\sf \frac{1}{3} x$ from both sides.

$\sf \frac{1}{2}x -\frac{1}{4}-\sf \frac{1}{3} x=\frac{1}{3}x+\frac{1}{2}-\sf \frac{1}{3} x$

$\sf \frac{1}{6}x+\frac{-1}{4} =\frac{1}{2}$

Step 3: Add $\sf \frac{1}{4}$ to both sides.

$\sf \frac{1}{6}x+\frac{-1}{4} +\frac{1}{4} =\frac{1}{2}+\frac{1}{4}$

$\sf \frac{1}{6}x=\frac{3}{4}$

$\sf x=\frac{9}{2}$

$\rule{300}{1}$

Verification if $\sf x=\frac{9}{2}$ .

$\sf \frac{\frac{9}{2} }{2} -\frac{1}{4}=\frac{\frac{9}{2} }{3}+\frac{1}{2}$

$\sf \frac{9}{2}\times \frac{1}{2}-\frac{1}{4}=\frac{9}{2}\times \frac{1}{3}+\frac{1}{2}$

$\sf \frac{9}{4}-\frac{1}{4}=\frac{9}{6}+\frac{1}{2}$

$\sf \frac{8}{4}=\frac{9}{6}+\frac{3}{6}$

$\sf \frac{8}{4}=\frac{12}{6}$

$\sf 2=2$

∴ $\sf x=\frac{9}{2}$ in the equation ⇒ $\sf \frac{x}{2} -\frac{1}{4}=\frac{x}{3}+\frac{1}{2}$

$\rule{300}{1}$

Additional Information :)

Algebra is all about puzzles. Here, $\sf x+9=19$ we simply need to find the value of 'x'. So here 'x' is equal to 10. We can say that the sum of 10 and 9 is 19. Over here 'x' is a variable.

Variable is an unknown value and is mostly represented in small alphabets. The value can vary.

Constant is a number that has a proper value. The value can't vary.

In an algebraic expression, we don't have an equal sign whereas in an algebraic equation, we have an equal sign.

Answer 2

Answer:

9/2 is answer dear friend