Question

can anyone send me the answer for 34th quest

Answer 1

Let the four terms be a, ar, ar^2 and ar^3

Given that, a + ar = 9
=> a(1+r) = 9........(1)


Also given, ar^2 + ar^3 = 36
=> ar^2( 1 + r) = 36

Putting a(1+r) in the above equation,

(r^2)*9 = 36
r^2 = 4
r = +2, - 2

It is given that r is positive so r = - 2 will be discarded.

Putting the value of r as 2 in equation (1),

a ( 1+2) = 9
a = 3

Thus the terms of the gp are

a = 3
ar = 3*2 = 6
ar^2 = 3*2*2 = 12
ar^3 = 3*2*2*2 = 24