Math, asked by harshitakhande27, 5 hours ago

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Answered by itzPapaKaHelicopter
3

(f) \: ( {6}^{2}  \times  {3}^{ - 2} )( {6}^{2}  \div  {3}^{ - 2} )

\sf \colorbox{pink} {Ans. (f)}

 =  \left(  {6}^{2} \times  \frac{1}{ {2}^{2} }  \right) \] \left( {6}^{2}   \div  \frac{1}{ {3}^{2} } \right) \]\[ \left[  {a}^{ - m}   =  \frac{1}{ {a}^{m} } \right] \]

 =  \left( 6 \times 6 \times  \frac{1}{3 \times 3} \right) \](36 \times 9)

 = 4 \times 9 \times 36 = 36 \times 36 = 1296

(g) \:  {5}^{0}  +  {3}^{0}  -  {2}^{0}

\sf \colorbox{pink} {Ans. (g)}

 =  {5}^{0}  +  {3}^{0}  -  {2}^{0}

 = 1 + 1 - 1

 = 1

(i) \:  \left(  \frac{ {a}^{3}  {b}^{2} }{ {ab}^{ 3} } \right) \] {}^{ - 3}

\sf \colorbox{pink} {Ans. (i)}

 = \left(  \frac{ {a}^{3}  {b}^{2} }{ {ab}^{ 3} } \right) \] {}^{ - 3}

 = ( {a}^{2}  \times  {b}^{2}  {)}^{ - 3}

 =  \left(  \frac{ {b}^{2} }{a} \right) \] {}^{3}

(j) \: \[ \left[  { \left(  \frac{1}{2} \right) \]}^{3}  \right] \] {}^{2}  \times  { \left(  \frac{1}{2} \right) \]}^{ - 2}  \times  {2}^{ - 1}  \times 6

\sf \colorbox{pink} {Ans. (j)}

 = \[ \left[  { \left(  \frac{1}{2} \right) \]}^{3}  \right] \] {}^{2}  \times  { \left(  \frac{1}{2} \right) \]}^{ - 2}  \times  {2}^{ - 1}  \times 6

 = \[ \left[  { \left(  \frac{1}{2} \right) \]}^{6}  \right]  \times  {2}^{2}  \times  \frac{1}{2}  \times 6

 =  \frac{1}{ {2}^{6} }  \times 2 \times 6

 =  \frac{1}{64}  \times 12

 =  \frac{3}{16}

(k) \: ( {3}^{0}  +  {2}^{0} ) + ( {3}^{0}  -  {2}^{0} )

\sf \colorbox{pink} {Ans. (k)}

 = ( {3}^{0}  +  {2}^{0} ) + ( {3}^{0}  -  {2}^{0} )

 = (1 - 1)(1 + 1) \: [As,  {a}^{0}  = 1,a≠0]

 = 0 \times 2 = 0

 \\  \\  \\  \\  \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}

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