Question

can anyone slove this question
irrelevant answer will be reported ​

Answer 1

Answer:

$x = ( - 7)$

Step-by-step explanation:

$3( \frac{3x - 1}{2x + 3} ) - 2( \frac{2x + 3}{3x - 1} ) = 5 \\ \frac{9x - 3}{2x + 3} - \frac{4x - 6}{3x - 1} = 5 \\ \frac{(9x - 3)(3x - 1) - (4x - 6)(2x + 3)}{(2x + 3)(3x - 1)} = 5 \\ \frac{9x(3x - 1) - 3(3x - 1) - 4x(2x + 3) - 6(2x + 3)}{2x(3x - 1) + 3(3x - 1)} = 5 \\ \frac{27 {x}^{2} - 9x - 9x + 3 - 8 {x}^{2} - 12x - 12x - 18 }{6 {x}^{2} - 2x + 9x - 3} = 5 \\ \frac{27 {x}^{2} - 8 {x}^{2} - 9 x - 9x - 12x - 12x + 3 - 18}{6 {x}^{2} - 2x + 9x - 3 } = 5 \\ \frac{19 {x}^{2} - 42x - 15 }{6 {x}^{2} + 7x - 3 } = 5 \\ 19 {x}^{2} - 42x - 15 = 5(6 {x}^{2} + 7x - 3) \\ 19 {x}^{2} - 42x - 15 = 30 {x}^{2} + 35x - 15 \\ 19 {x}^{2} - 30 {x}^{2} - 42x - 35x - 15 + 15 = 0 \\ ( - 11) {x}^{2} - 77x = 0 \\ 11 {x}^{2} + 77x = 0 \\ 11x(x + 7) = 0 \\ x + 7 = \frac{0}{11x} \\ x + 7 = 0 \\ x = ( - 7)$