Can anyone solve 18th question?
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It is given that
It is given that Principal (P) = 60000
It is given that Principal (P) = 60000Amount (A) = 79860
It is given that Principal (P) = 60000Amount (A) = 79860 Period (n) = 1 1/2 years = 3 half-years
It is given that Principal (P) = 60000Amount (A) = 79860 Period (n) = 1 1/2 years = 3 half-years We know that
It is given that Principal (P) = 60000Amount (A) = 79860 Period (n) = 1 1/2 years = 3 half-years We know that A/P =
It is given that Principal (P) = 60000Amount (A) = 79860 Period (n) = 1 1/2 years = 3 half-years We know that A/P =Substituting the values
It is given that Principal (P) = 60000Amount (A) = 79860 Period (n) = 1 1/2 years = 3 half-years We know that A/P =Substituting the values BY further calculation
It is given that Principal (P) = 60000Amount (A) = 79860 Period (n) = 1 1/2 years = 3 half-years We know that A/P =Substituting the values BY further calculation We get
It is given that Principal (P) = 60000Amount (A) = 79860 Period (n) = 1 1/2 years = 3 half-years We know that A/P =Substituting the values BY further calculation We get By cross multiplication
It is given that Principal (P) = 60000Amount (A) = 79860 Period (n) = 1 1/2 years = 3 half-years We know that A/P =Substituting the values BY further calculation We get By cross multiplication half-yearly
It is given that Principal (P) = 60000Amount (A) = 79860 Period (n) = 1 1/2 years = 3 half-years We know that A/P =Substituting the values BY further calculation We get By cross multiplication half-yearly p.a.
It is given that Principal (P) = 60000Amount (A) = 79860 Period (n) = 1 1/2 years = 3 half-years We know that A/P =Substituting the values BY further calculation We get By cross multiplication half-yearly p.a.Therefore, the rate of interest per annum compounded half-yearly is 20%
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