Question

can anyone solve 4th one plzzz

Answer 1

please follow me please

Answer 2

Answer:

$p(x) = {x}^{3} + 1 \: \: div. \: by \: x + 1 \\ \\ put \: \: x = - 1 \\ \\ p( - 1) = 0 \\ \\ so \: \: reminder \: \: is \: \: 0$