can anyone solve dizz. plzz.I'll mark brainliest
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to prove EF = ED
first we have to prove ∆ AEF ~= ∆EDC
AF = CD ( GIVEN )
< AFE = < CDE. ( GIVEN )
< E is common in both the ∆
so ∆ AEF ~= ∆ EDC
HENCE PROVED
so EF = ED (CPCT )
HOPE THIS ANSWER WILL HELP U !!
PLZZZ MARK MY ANSWER AS BRAINLIEST !!!!
first we have to prove ∆ AEF ~= ∆EDC
AF = CD ( GIVEN )
< AFE = < CDE. ( GIVEN )
< E is common in both the ∆
so ∆ AEF ~= ∆ EDC
HENCE PROVED
so EF = ED (CPCT )
HOPE THIS ANSWER WILL HELP U !!
PLZZZ MARK MY ANSWER AS BRAINLIEST !!!!
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