Question

can anyone solve dizz. plzz.I'll mark brainliest

Answer 1

to prove EF = ED
first we have to prove ∆ AEF ~= ∆EDC

AF = CD ( GIVEN )
< AFE = < CDE. ( GIVEN )
< E is common in both the ∆

so ∆ AEF ~= ∆ EDC
HENCE PROVED


so EF = ED (CPCT )



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