Question

can anyone solve it....​

Answer 1

Answer:

$t_{1} = mg \\ \\ t_{2} = mg \sin( {30}^{0} ) \\ \\ \frac{ t_{1} }{ t_{2}} = \frac{1}{ \sin( {30}^{0} ) } = \frac{1}{ \frac{1}{2} } = 2$