can anyone solve it maths of class 9
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the Area (triangle AOD) as Area(I)
The Area (triangle BOC ) as Area(II)
Area (triangle AOB) as Area(III)
Given that
Area(I)=Area(II)
So,
Area(I)+Area(III)=Area(II)+Area(III)
This gives us that,
Area(triangle ADB)=Area(triangle ACB)
So, AB must be parallel to DC ..(as triangles on the same base and equal in area must lie between same parallels)
So, ABCD is a trapezium as one pair of opposite sides is parallel.
The Area (triangle BOC ) as Area(II)
Area (triangle AOB) as Area(III)
Given that
Area(I)=Area(II)
So,
Area(I)+Area(III)=Area(II)+Area(III)
This gives us that,
Area(triangle ADB)=Area(triangle ACB)
So, AB must be parallel to DC ..(as triangles on the same base and equal in area must lie between same parallels)
So, ABCD is a trapezium as one pair of opposite sides is parallel.
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