Can Anyone Solve it
No SLILY Answer
PLS Answer On 16TH Is My TEST
Attachments:
Answers
Answered by
1
Answer
Given: ABC is a triangle; AD is the exterior bisector of 4A and meets BC
produced at D; BA is produced to F.
To prove: AB/AC = BD/DC
Construction: Draw CE||DA to meet AB at E.
Proof: In A ABC. CE||AD cut by AC.
∠CAD = ∠ACE (Alternate angles)
Similarly CE || AD cut by AB
∠FAD = ∠AEC (corresponding angles)
AC = AE (by isosceles △ theorem)
Now in △BAD, CE || DA
AE = DC (BPT)
AB BD
But AC = AE (proved above)
AC = DC
AB = BD or
AB/AC = BD/DC (proved).
hope it helps!!!
love,
Anjali
Similar questions