Math, asked by smirithireddy3, 1 month ago

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Answered by Anonymous
93

Construct BD of 1 unit length perpendicular to OB as fig. Join OD

Construct BD of 1 unit length perpendicular to OB as fig. Join OD

By Pythagoras theorem,

 \rm \: OD =   \sqrt{\sqrt{2 }^{2} +  {1}^{2}}   \\  \\  \rm \implies \sqrt{2 + 1}  \\  \\  \rm \implies \sqrt{3}

Using a compass, with centre O and radius OD, draw an arc which

Using a compass, with centre O and radius OD, draw an arc which intersects the number line at the point L right side to 0. Then

′ L ′ corresponds to  \rm \sqrt{3}

From this we can conclude that many points on the number line can be represented by irrational numbers also.

Note:-

In the same way, we can locate  \rm \sqrt{n} for any positive integers n, after  \rm\sqrt{n−1	} has been located.

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