Math, asked by disastergirl20, 7 months ago

can anyone solve no. 3 questions answer​

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Answers

Answered by Anonymous
7

Answer:

Using formula

log mn =log m +log n

log m/n = log m - log n

&

log( m to the power n) = n log m 

Solution :-

(1). log 36 = log 9*4 = log 9+ log 4= log 3² +log2² = 2log 3 +2log 2  

(2). log 144 = log 16*9 = log 16 +log 9 = log 2²×2² +log 3²

 = log 2² +log 2² +log 3² =2log 2 +2 log 2 + 2log3 = 4log 2 + 2log 3

(3). log 4.5 = log 45/10 = log 45 - log 10 = log 5×3² - 1 (this can not be expressed in log 2 ,log 3 )  = log 5 +2log 3 -1  

(4). log 26/51 - log 91/ 119 = log 26/51 ÷ 91/119 = log 26*119 /51*91 =

log 3094 / 4641 = log  2/3 =log 2 -log 3

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