Question

Can anyone solve Q4,5,6 by using Quadratic Formula

Answer 1

5.   2(2x-1/x+3)-3(x+3/2x-1)=5

or, {2(2x-1)²-3(x+3)²}/(x+3)(2x-1)=5

or, {2(4x²-4x+1)-3(x²+6x+9)}/(2x²+6x-x-3)=5

or, 8x²-8x+2-3x²-18x-27=5(2x²+5x-3)

or, 5x²-26x-25=10x²+25x-15

or, 5x²-10x²-26x-25x-25+15=0

or, -5x²-51x-10=0

or, 5x²+50x+x+10=0

or, 5x(x+10)+1(x+10)=0

or, (x+10)(5x+1)=0

Either, x+10=0

or, x=-10

Or, 5x+1=0

or, 5x=-1

or, x=-1/5

∴, x=10,-1/5 Ans.

6.   while giving the value of x=1,

we get 2(3/-1)-9(-1/3)=0

-6+3=0

=-3.

the answer of question 4 is in attachment