can anyone solve ques 21 2nd part??
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in triangle OSP AND OTP
OS=OT
OP=OP
SP=PT
Therefore,
by proving similarity(SSS similarity criteria)
<OPS=<OPT=1/2×<SPT
=1/2×120
=60°
so in right triangle OPS
cos60°=adjacent/hypotenuse
1/2=PS/OP
OP=2PS
PROVED
hope it helps!!
OS=OT
OP=OP
SP=PT
Therefore,
by proving similarity(SSS similarity criteria)
<OPS=<OPT=1/2×<SPT
=1/2×120
=60°
so in right triangle OPS
cos60°=adjacent/hypotenuse
1/2=PS/OP
OP=2PS
PROVED
hope it helps!!
Anonymous:
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