Can anyone solve questions 2 & 3 please?
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Hii mate
I will answer the third question
x^3-4x^2-x+1=(x-2)^3
x^3-4x^2-x+1=x^3-3x^2×2+3x×2^2-2^3
x^3-4x^2-x+1=x^3-6x^2+12x-8
x^3-x^3-4x^2+6x^2-x-12x+1+8=0
2x^2-13x+9=0
yes it is in the form ax^2+bx+c
therefore it is a quadratic equation
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answer of second question :
3x^2-4root 3x+4=0
b^2-4ac
=(-4root3)^2 - 4×3×4
=16×3-12×4
=48-48
=0
b^2-4ac=0
therefore equation has two equal real roots
hope it helps you
thank you
I will answer the third question
x^3-4x^2-x+1=(x-2)^3
x^3-4x^2-x+1=x^3-3x^2×2+3x×2^2-2^3
x^3-4x^2-x+1=x^3-6x^2+12x-8
x^3-x^3-4x^2+6x^2-x-12x+1+8=0
2x^2-13x+9=0
yes it is in the form ax^2+bx+c
therefore it is a quadratic equation
@@@@@@@@@@@@@@@@@@@@@@@@@$$$$
answer of second question :
3x^2-4root 3x+4=0
b^2-4ac
=(-4root3)^2 - 4×3×4
=16×3-12×4
=48-48
=0
b^2-4ac=0
therefore equation has two equal real roots
hope it helps you
thank you
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