Question

Can anyone solve questions 2 & 3 please?

Answer 1

Hii mate
I will answer the third question

x^3-4x^2-x+1=(x-2)^3

x^3-4x^2-x+1=x^3-3x^2×2+3x×2^2-2^3

x^3-4x^2-x+1=x^3-6x^2+12x-8

x^3-x^3-4x^2+6x^2-x-12x+1+8=0

2x^2-13x+9=0

yes it is in the form ax^2+bx+c

therefore it is a quadratic equation
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answer of second question :

3x^2-4root 3x+4=0

b^2-4ac

=(-4root3)^2 - 4×3×4

=16×3-12×4

=48-48

=0

b^2-4ac=0

therefore equation has two equal real roots

hope it helps you

thank you