Question

can anyone solve the problems
​

Answer 1

Answer:

Let the intercepts cut by the given line on the axes be a and b.

It is given that,

a+b= 1....(1)

and ab=−6....(2)

On solving equation (1) and (2), we obtain

a=3 and b=−2 or a=−2 and b=3

It is known that the equation of the line whose intercepts on the axes are a and b is

a

x

+

b

y

=1 or bx+ay−ab=0.

case1: a=3 and b=−2

In this case the equation of the line is −2x+3y+6=0⇒2x−3y=6

case2: a=−2 and b=3

In this case the equation of line is 3x−2y+6=0⇒−3x+2y=6

Thus, the required equation of the lines are 2x−3y=6 and −3x+2y=6.