can anyone solve the second question
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by elimination
(4x+5y=0) ×2 (1)
8x +10y=0 subtract 1 &2
8x-15y=5 (2)
- + -
____________
25y=-5
y= -1/5
put in 1
4x+(-1/5) =0
x= 1/4
by substitution
4x+5y=0 (1)
8x-15y=5 ( 2)
from 1
x =-5y/4
put in 2
8(-5y/4) -15y=5
-10y-15y=5
-25y=5
y=-5/25
y=-1/5
put in 1
x=-5/4×-1/5
x=1/4
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