Math, asked by Sandeep03edu, 1 year ago

Can anyone solve these question no. 38 and 41

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Answered by Yash0007
0
38)--->

Given length of the room = 15m

Width of the carpet = 75 cm = 75/100 m = 3/4 m (since 100 cm = 1 m. So 75 cm = 75/100 m)

Let length of the carpet is L.

Given cost of the carpet per meter = 80 rupees

Cost of the carpet required for the room = 80*L

Again given that total cost of the carpeting = 19200

So 80*L = 19200

=> L = 19200/80

=> L = 240 m

Now area of the carpet required for the room = Length *breadth

= 3/4 * 240

= 3* 60

= 180 m2

Now let width of the room is b.

Area of the room = 15*b m2

So 15*b = 180

=> b = 180/15

=> b = 12

So width of the room is 12 m


41)------>

Radius of a garden roller (r) = 1.4 / 2 = 0.7 m

and length of the garden roller (h) = 2 m

∴ Curved surface area of garden roller = 2πrh .

So, the area levelled of a garden roller in one revolution is 8.8 m2.

Now, area levelled of a garden in 5 revolutions = 8.8 x 5= 44m²
Answered by Anonymous
1

Electricity is useful for Many things that occur in the physical world are known as janhana( janahana means people) with the electric charge The electric charge was released in the light of the sky power of lightning electricity used as a source of energy, etc. Before the development of the Maxwell's equation, it is considered to be the first thing in the form of a physical phenomenon of energy.

:):)

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