Question

can anyone solve these questions it is very urgent
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Answer 1

Answer:

$a = equal sid \\ \\ </p><p>x = unequal side \\ \\ Area \: of \: isosceles \: triangle \: = \sqrt{ {{a}^{2} } - \frac{ {x}^{2} }{4} } \\ = \: \sqrt{{ {6}^{2} } - \frac{ {8}^{2} }{4} } \\ = \sqrt{36 - \frac{64}{4} } \\ = \sqrt{ \frac{144 - 64}{4} } \\ = \sqrt{ \frac{80}{4} } \\ = \sqrt{20} \\ = 4.47 {m}^{2}$

$7) \\ 3 \sqrt{2} + 7 \sqrt{2} + \sqrt{2} - 5 \sqrt{3} \\ = 4 \sqrt{2} + 2 \sqrt{3}$

$9) \\ R = 2r \\ volume \: of \: sphere \: = 4/3 πr³ \\ = \frac{4}{3} \times \frac{22}{7} \times 2r \times 2r \times 2r \\ = 33.52 \: {r}^{3 } ( \: answer) \\ \\ { \huge{ \boxed{ \pink{ \boxed{ \purple{ \boxed{ \orange{ \boxed{ \ hope \: this \: helps \: u}}}}}}}}}$