Question

can anyone solve this 14 number question

Answer 1

sin x = BC/AC
        = √3/2
now we know that sin 60°=√3/2
therefore x°=60°
tan x=BC/AB
 now we know that AB²+BC²=AC²
⇒y²+3=4
⇒y=1
therefore tan x=√3/1 = √3

similarly use cos x to find the the value of y which is 1 unit as seen earlier.
 

Answer 2

$y = \sqrt{ac {}^{2} - bc {}^{2} }$

$y = \sqrt{2 {}^{2} - ( \sqrt{3} ) {}^{2} }$

$y = \sqrt{4 - 3} = \sqrt{1}$

y = ab = 1

1) sinx = bc/ac


$sinx \: = \sqrt{3} \div 2$

2)
$sinx = \sqrt{3} \div 2$

x = 60


$3) \: \: \: \: tanx \: = \sqrt{3} \div 1$

4) As x = 60

cos 60 = ab/ac

1/2 = y/2

y = 2/2 = 1



Thanks