Question

can anyone solve this​

Answer 1

Step-by-step explanation:

hope this answer will help you

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Answer 2

Answer:

this is your answer

Step-by-step explanation:

let ABC = ⚠PQR

and AD,PS are the median...

to prove =

$\frac{area \: of \: triangle \: abc}{area \: of \: tringle \: pqr } = \frac{ {ad}^{2} }{ {ps}^{2} }$

proof: abc &⚠pqr are similar....

$\frac{ab}{pq} = \frac{bc}{qr} = \frac{ac}{pr}$

angle A = angle P.

angle B = angle Q.

and

angle C = angle R.

. .

. AP and PS are the median .

BD = DC = 1/2*BC..

QS = SR = 1/2*QR..

now.. from abc& pqs...

by SAS. rule ABD = PQS

. .

.

$\frac{area \: of \: triangle \: abc}{area \: of \: triangle \: pqr} = \\ \frac{ \frac{1}{2} \times bc \times ad }{ \frac{1}{2} \times qr \times ps } = \\ \frac{bc}{qr} \times \frac{ad}{ps}$

$\frac{ad}{ps} \times \frac{ad}{ps} = \frac{ {ad}^{2} }{ {ps}^{2} }$

hence verify..............