Math, asked by SkywalkerS19, 8 months ago

Can anyone solve this?

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Answers

Answered by Cosmique
6

\underline{ \large{  \bf{question}}}

Solve :

 \bf {3( {2}^{x}  + 1) -  {2}^{(x + 2) } + 5 = 0 }

\underline{ \large{ \bf{solution}}}

3( {2}^{x}  + 1) -  {2}^{x + 2}  + 5 = 0 \\  \\  3 \times  {2}^{x}  + 3 -  {2}^{x}  \times  {2}^{2}  + 5 = 0

taking 2^x common

 {2}^{x} (3 -  {2}^{2} ) + 3 + 5 = 0 \\  \\  {2}^{x} ( - 1) + 8 = 0 \\  \\  -  {2}^{x}  =  - 8 \\  \\  \cancel{ - } {2}^{x}  =  \cancel{ - }8 \\  \\  {2}^{x}  =  {2}^{3}

Comparing LHS and RHS

we will get

\boxed{ \bf{ x = 3}}

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