can anyone solve this?
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laxmipriyapradoyptdj:
can anyone send a picture explaining this problem?
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I think understand it
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cos A=1/2=base/hypotenuse
let the base be x and hypotenuse 2x
using Pythagoras Theorem
x²+perpendicular ²=(2x)²
perpendicular ²=4x²-x²
perpendicular=√3x
tanA=perpendicular/hypotenuse=√3x/x=√3
similarly we get the value of tanB 1
put the values and get ur answer .
mark as brainliest
let the base be x and hypotenuse 2x
using Pythagoras Theorem
x²+perpendicular ²=(2x)²
perpendicular ²=4x²-x²
perpendicular=√3x
tanA=perpendicular/hypotenuse=√3x/x=√3
similarly we get the value of tanB 1
put the values and get ur answer .
mark as brainliest
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