Math, asked by manjali, 1 year ago

can anyone solve this?

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Answers

Answered by pushpakRuhil
1

 {2}^{4x}  =  \sqrt{32}  =  {32}^{ \frac{1}{2} }
now 32= 2*2*2*2*2
 =  {2}^{5}
so,
 {32}^{ \frac{1}{2}  }  =  {2}^{ \frac{5}{2} }



on comparing powers (as the bases are now same)

4x = 5/2
x= 5/(2×4)


x =  \frac{5}{8}



Answered by wrongway265
0

Answer:

2

4x

=

32

=32

2

1

now 32= 2*2*2*2*2

= {2}^{5}=2

5

so,

{32}^{ \frac{1}{2} } = {2}^{ \frac{5}{2} }32

2

1

=2

2

5

on comparing powers (as the bases are now same)

4x = 5/2

x= 5/(2×4)

x = \frac{5}{8}x=

8

5

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