can anyone solve this
Attachments:
Answers
Answered by
2
9) substitute x=-3,andy=5 in 2 (x.....
2 ((-4)-30+75-25
-8-30+75-25
-38+50
-22
ok
2 ((-4)-30+75-25
-8-30+75-25
-38+50
-22
ok
shraddhabolegaon1:
sry rong calculations
Answered by
1
5. 4(x^2)-3xy+7x+5(x^2)+7xy-5x
= (4(x^2)+5(x^2))+(-3xy+7xy)+(7x-5x)
= 9(x^2)+4xy+2x
(9(x^2)+4xy+2x)-(4xy-7(x^2))
= 9(x^2)+4xy+2x-4xy+7(x^2)
= 16(x^2)+0+2x
= 16(x^2)+2x
6. (((-2)+5)/3)-1
= (3/3)-1
= 1-1
= 0
7. (a^2)-(b^2)+4ab
= (1^2)-(-2^2)+4*1*(-2)
= 1-4-8
= -11
8. 5x-2(x^2)+b = -3
-5-2+b = -3
-7+b = -3
b = 7-3
= 4
9. 2((x^2)+2xy)+5-xy+(y^2)
= 2(x^2)+4xy+5-xy+(y^2)
= 2(-3^2)+4*(-3)*5+5-(-3)*5+(5^2)
= 18-60+5+15+25
= 3
= (4(x^2)+5(x^2))+(-3xy+7xy)+(7x-5x)
= 9(x^2)+4xy+2x
(9(x^2)+4xy+2x)-(4xy-7(x^2))
= 9(x^2)+4xy+2x-4xy+7(x^2)
= 16(x^2)+0+2x
= 16(x^2)+2x
6. (((-2)+5)/3)-1
= (3/3)-1
= 1-1
= 0
7. (a^2)-(b^2)+4ab
= (1^2)-(-2^2)+4*1*(-2)
= 1-4-8
= -11
8. 5x-2(x^2)+b = -3
-5-2+b = -3
-7+b = -3
b = 7-3
= 4
9. 2((x^2)+2xy)+5-xy+(y^2)
= 2(x^2)+4xy+5-xy+(y^2)
= 2(-3^2)+4*(-3)*5+5-(-3)*5+(5^2)
= 18-60+5+15+25
= 3
Similar questions