Question

can anyone solve this​

Answer 1

HELLO HERE IS YOUR ANSWER.....

GIVEN, AM = 4 , BM = 3 AND

MC = 5

THEN, WE CAN FIND THE VALUE OF 'AB' AND 'AC' BY USING PYTHAGORAS THEOREM....

IN ∆ ABM,

AB^2 = AM^2 + BM^2

OR AB^2 = 4^2 + 3^2

OR AB^2 = 16+9

OR AB^2 = 25

OR AB = 5

AGAIN IN ∆ AMC,

AC^2 = 4^2+5^2

OR AC^2 = 41

OR AC = 6.4

NOW, sec B = AB/BM = 5/3

cosec C = AC/AM = 6.4/4

cot C = MC/AM = 5/4

AND sin^2 B + cos^2B

= ( AM/AB)^2 + (BM/AB)^2

= (4/5)^2 + (3/5)^2

= 16/25 + 9/25

= (16+9)/25

= 25/25

= 1

FROM THIS,WE CAN WRITE AS...

sin^2 B + cos^2 B = 1

HOPE ITS HELPFUL...DONT FORGET TO

GIVE THANKS AND MARK BRAINLIEST.