Question

can anyone solve this??​

Answer 1

Answer:

i) 7b23/3

divisibility rule of 3 is that the sum of digits is a multiple of 3

7+b+2+3=(12+b)/3

So the smallest possible value of b

So that the number is divisible by 3 is 0

ii) from divisibility test, if a number is divisible by 3 then sum of its digits must be divisible by 3.

8+3+b+4+9=b+24

so for b=0,3,6,9. 83b49 is divisible by 3

Answer 2

Answer:

23)

(1) 3,6,9,0

(2)3,6,9,0

24) let the angles be x,2x,3x,4x

therefore x+2x+3x+4x+=360

       or     10x = 360

                   x =36

therefore angles are 36,72,108 and 144

$(7m-8n)^{2} +(7m-8n)^{2} \\=(49m^{2} -112mn +64n^{2} ) + (49m^{2} -112mn +64n^{2} )$

$98m^{2} - 224mn +128n^{2}$

(2)

$99^{2} =(100-1)^{2}$

$=10000 - 200 + 1\\=9801$

26

(1)441

(2)231

please mark me as brainliest please