Question

Can anyone solve this?​

Answer 1

So if we take a triangle with base = b, height = h

Area(Δ) = b x h /2

Let new base and height be b' and h' where,

b' = 3b, h' = h/2

So,

Area(new Δ) = b' x h' /2 = 3b x h /(2 x 2)

=3/2 x (b x h /2) = 3/2 times the original triangle

∴ The area of the triangle increases 3/2 times when its base is tripled and height is halved.

Hope I helped ☺☻

Answer 2

Step-by-step explanation:

first triangle

base=x

height=y

area=xy/2

second triangle

base=3x

height=y/2

area=3xy/4

area is increased by=(3xy/4)/ (xy/2)=1.5