Can anyone solve this?
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So if we take a triangle with base = b, height = h
Area(Δ) = b x h /2
Let new base and height be b' and h' where,
b' = 3b, h' = h/2
So,
Area(new Δ) = b' x h' /2 = 3b x h /(2 x 2)
=3/2 x (b x h /2) = 3/2 times the original triangle
∴ The area of the triangle increases 3/2 times when its base is tripled and height is halved.
Hope I helped ☺☻
Answered by
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Step-by-step explanation:
first triangle
base=x
height=y
area=xy/2
second triangle
base=3x
height=y/2
area=3xy/4
area is increased by=(3xy/4)/ (xy/2)=1.5
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