Question

can anyone solve this?​

Answer 1

$\huge \fbox \orange{Answer:}$

$\textbf{First let us solve } a + (b + c) \: \textbf{Then,}$

$= \frac{ - 11}{27} + \begin{cases} & \text{} \\ & \text{}\end{cases} \frac{4}{9} + ( \frac{ - 5}{18} )$

$= \frac{ - 11}{27} + \frac{4}{9} - \frac{5}{18}$

$= \frac{ - 22 + 24 - 15}{54}$

$= \frac{ - 37 + 24}{54}$

$= \frac{ - 13}{54}$

$\textbf{Now, Let us Solve } (a + b) + c$

$= ( \frac{ - 11}{27} + \frac{4}{9}) + \frac{ - 5}{18}$

$= \frac{ - 11}{27} + \frac{4}{9} - \frac{5}{18}$

$= \frac{ - 22 + 24 - 15}{54}$

$= \frac{ - 37 + 24}{54}$

$= \frac{ - 13}{54}$

$\textbf{so ,} \: a + (b + c) \: \textbf{are \: aqual \: } \: (a + b) + c$

$\\ \\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$