Question

can anyone solve this ?? ​

Answer 1

Answer:

the answer is give above hope it helps and please mark me the brainliest

Answer 2

Hlo mate, here is your step-by-step answer:

In rectangle ABCD,

In rectangle ABCD, All 4 angles are 90°, thus, ∠ABC = 90°.

Now in ∠CEB:∠ECB = 3:2.

Let, ∠CEB = 3x°, and ∠ECB= 2x°.

Therefore,

=> 90° + 3x + 2x = 180°

=> 5x = 90°

=> x = (90/5)°

=> x = 18°

Thus, ∠CEB = 3x° = (3 * 18)° = 54°.

∠CEA = ∠ECB + ∠CBE {Exterior angle is equal to the sum of two opposite interior angle}

= 2x° + 90° = (2*18 + 90)°

= 126°

Now, opposite sides of a rectangle are parallel to each other.

Therefore, AB || CD.

EF is the transversal.

∠DCF = ∠CEA = 126° {Corresponding angles}

Hope it helps.. please mark my answer as the brainliest :)