Question

can anyone solve this​

Answer 1

$\huge\boxed{\fcolorbox{red}{blue}{♡︎Answer ࿐}}$

$Given, Lim ( x - \infty )((x {}^{2} + 1) \\ - 1x - b) = 0$

$= lim \: ( \frac{(1 - a)x {}^{2} - (a + b)x + 1(1 - b)}{x + 1}$

$it \: is \: possible \: only \: when \: 1a = 0 \\ (a + b) = 0$

$thus \: a \: = 1 \: and \: b = - 1$

Answer 2

Answer:

Step-by-step explanation:

Limit(x-∞)(x²+1)(-1x-b)=0.