can anyone solve this
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perimeter of isosceles = 2a + b
==> 14 cm = 2(5x)+4x
==> 14 = 10x+4x
==> 14 = 14x
==> x = 14/14
==> x = 1
so, 5x = 5(1) = 5
base = 4(1) = 4
so, sides are 5,5,4
area of triangle =>
s = a+b+c/2 ==> 5+5+4/2 ==> 14/2 ==> 7
s = root 7 * root 7-5 * root 7-5 * 7-4
==> root 7 * root 2 * root 2 * root 3
==> 2 root 21 cm^2
so, answer = d
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