Question

can anyone solve this

Answer 1

angle BAR is equal to 40 degrees.
since any angle formed on a semi circle is a right angle.
therefore angle BRA is equal to 90 degrees .
therefore angle BAR is 90-50=40 degrees.
angle PBA is equal to 90-55=35 degrees.

Answer 2

angle PAB = 55° , angle PBQ = 25°

angle ABR = 50°

since , AB is parallel to PQ

then the formed triangle APB will be a right angle triangle .

thus angle APB = 90°

in triangle, APB

sum of all the angles of triangle = 180°

angle APB + angle PAB + angle PBA = 180°

90° + 55° + angle PBA= 180°

angle PBA = 180° - 145° = 35°

angle PBA = 35°

opposite angles of this quadrilateral figure will be equal.

thus angle PAR = angle PBR

angle PAB + angle BAR = angle PBA + angle ABR

55 + angle BAR = 35° + 50°

angle BAR = 30°

Answer:

angle PBA = 35° and angle BAR = 30°