Can anyone solve this eq root7root7............... Upto infinite
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Answered by
0
hey mate
hope this helps u
if root7 root7 is upto infinite
the definitely the answer will be
ANY MULTIPLE OF 7
it can be till infinity also
MARK AS BRILLIANEST
Answered by
0
Your answer is in pic.......
Let root7 root 7 root 7..... = x
Then
Root7 x = x
Squaring,
7x = x^2
x^2 - 7x = 0
x( x - 7) = 0
x = 0 or x = 7.
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