Question

can anyone solve this for me.
please give the full solution.​

Answer 1

Answer:THIS IS YOUR ANSWER!!!

Step-by-step explanation:

Area of four walls =2(d+b)h=236×4.5=1062 m  

2

 

Given, cost of painting four walls =Rs 8.40/m  

2

 

∴ Total cost =1062×8.40=Rs 8920.8

Answer 2

Step-by-step explanation:

Given,

• The floor of a rectangular hall has a perimeter 236m
• Height of the rectangular hall is 4.5m
• Cost of painting is 8.40per square meter.

To find

The cost of painting its four walls

Solution

Perimeter (P) = 236m

Area of four walls is 2(l+b) × h

P = 2(l + b)

Substituting the values of perimeter and height

$\pmb{Area = 1062m ^ 2} \\ \pmb{ Area = 236 \times 2.5 \times m ^ 2}$

• The area of four walls is 1062m2
• The cost of painting 1m2 = Rs8.40 per square meter

Cost of painting 4 walls is

$\pmb{A \times rs \: 8.40 }\\ \bf{=1620 \times 8.40} \\ \pmb{rs \: 8920.80}$$\purple{ \bf \: The \: cost \: of \: painting \: four \: walls(doors \: and \: windows \: ignored) \: of \: a \: rectangular} \\ \purple{\bf\: hall \: of\: perimeter \: 236m, \: height \: 4.5m \: if \: the \: cost \: of \: painting \: is \: rs8.40 = 8920.80}$

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