can anyone solve this now
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Answered by
8
Heya !!
4a² - 15a - 4 = 0
4a² - 16a + a - 4 = 0
4a ( a - 4 ) + 1 ( a - 4 ) = 0
( a - 4 ) ( 4a + 1 ) = 0
( a - 4 ) = 0 or ( 4a + 1 ) = 0
a = 4 or a = -1/4.
4a² - 15a - 4 = 0
4a² - 16a + a - 4 = 0
4a ( a - 4 ) + 1 ( a - 4 ) = 0
( a - 4 ) ( 4a + 1 ) = 0
( a - 4 ) = 0 or ( 4a + 1 ) = 0
a = 4 or a = -1/4.
niya25:
Thanks alot
Answered by
3
Hey user !
So here's u r answer !
__________________
a^2 - 15 a - 4 = 0
4a^2 - 16a + a - 4 = 0
4 a ( a - 4 ) + 1 ( a - 4 ) = 0
4 a + 1 = 0 , a - 4 = 0
a = - 1 / 4 , a = + 4
______________________
So here's u r answer !
__________________
a^2 - 15 a - 4 = 0
4a^2 - 16a + a - 4 = 0
4 a ( a - 4 ) + 1 ( a - 4 ) = 0
4 a + 1 = 0 , a - 4 = 0
a = - 1 / 4 , a = + 4
______________________
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