Physics, asked by Anonymous, 4 months ago

Can anyone solve this please please please in copy right answer physics class 9
with solution I will Mark his or her as brainliest​

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Answers

Answered by Ekaro
5

All three questions are based on newton's second law of motion. As per this law, Force is measured as the product of mass and acceleration.

Question - 2)

What would be the force required to produce an acceleration of 2m/s² in a body of mass 12kg? What would be the acceleration if the force were doubled?

Answer - 2)

  • Mass = 12kg
  • Acceleration = 2m/s²

➝ F₁ = m × a₁

➝ F₁ = 12 × 2

F₁ = 24 N

In second case force is doubled.

  • F₂ = 2F₁ = 48N

➝ F₂ = m × a₂

➝ 48 = 12 × a₂

a₂ = 4 m/s²

________________________________

Question - 3)

A man pushes a box of mass 50kg with a force of 80N. What will be the acceleration of the box? What would be the acceleration if the mass were halved?

Answer - 3)

  • Mass = 50kg
  • Force = 80N

➝ F = m₁ × a₁

➝ 80 = 50 × a₁

➝ a₁ = 8/5

a₁ = 1.6 m/s²

In second case acceleration is halved.

  • m₂ = m₁/2 = 25kg

➝ F = m₂ × a₂

➝ 80 = 25 × a₂

➝ a₂ = 80/25

a₂ = 3.2 m/s²

________________________________

Question - 4)

A certain force of exerted for 1.2s raises the speed of an object from 1.8m/s to 4.2m/s. Later the same force is applied for 2 second. How much does the speed change in 2s?

Answer - 4)

  • t = 1.2 s
  • u = 1.8 m/s
  • v = 4.2 m/s

From the first equation of motion,

➝ v = u + at

➝ 4.2 = 1.8 + 1.2a

➝ 2.4 = 1.2a

a = 2 m/s²

Now acceleration remains constant.

Change in velocity in next second 2 s is given by

➝ a = ∆v/t

➝ 2 = ∆v/2

∆v = 4 m/s

Answered by Anonymous
2

Answer:

All three questions are based on newton's second law of motion. As per this law, Force is measured as the product of mass and acceleration

Question - 2)

What would be the force required to produce an acceleration of 2m/s² in a body of mass 12kg? What would be the acceleration if the force were doubled?

Answer - 2)

Mass = 12kg

Acceleration = 2m/s²

➝ F₁ = m × a₁

➝ F₁ = 12 × 2

➝ F₁ = 24 N

In second case force is doubled.

F₂ = 2F₁ = 48N

➝ F₂ = m × a₂

➝ 48 = 12 × a₂

➝ a₂ = 4 m/s²

________________________________

Question - 3)

A man pushes a box of mass 50kg with a force of 80N. What will be the acceleration of the box? What would be the acceleration if the mass were halved?

Answer - 3)

Mass = 50kg

Force = 80N

➝ F = m₁ × a₁

➝ 80 = 50 × a₁

➝ a₁ = 8/5

➝ a₁ = 1.6 m/s²

In second case acceleration is halved.

m₂ = m₁/2 = 25kg

➝ F = m₂ × a₂

➝ 80 = 25 × a₂

➝ a₂ = 80/25

➝ a₂ = 3.2 m/s²

________________________________

Question - 4)

A certain force of exerted for 1.2s raises the speed of an object from 1.8m/s to 4.2m/s. Later the same force is applied for 2 second. How much does the speed change in 2s?

Answer - 4)

t = 1.2 s

u = 1.8 m/s

v = 4.2 m/s

From the first equation of motion,

➝ v = u + at

➝ 4.2 = 1.8 + 1.2a

➝ 2.4 = 1.2a

➝ a = 2 m/s²

Now acceleration remains constant.

Change in velocity in next second 2 s is given by

➝ a = ∆v/t

➝ 2 = ∆v/2

➝ ∆v = 4 m/s

Explanation:

UNNIE

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