Question

can anyone solve this pls i will mark as brainliest

Answer 1

Answer:

Explanation:

1. Acceleration along AB = 10m/s

Acceleration along BC=0m/s

Acceleration along CD=15m/s

2.Distance=1/2+(5+10)*30=225m

3.Distance travelled after the brakes = 30m

4.Average speed = total distance/total time = 225/10=22.5m/s