Question

Can anyone solve this plz ​

Answer 1

Answer:

(p x ) if it is useful please follow

me

Answer 2

Answer:

$p(x) = {x}^{2} - 3x + 2 \\ so \: p(0) = {0}^{2} - 3 \times 0 + 2 \\ = 0 - 0 + 2 \\ = 2 \\ so \: p(2) = {2}^{2} - 3 \times 2 + 2 \\ = 4 - 6 + 2 \\ = 0 \\ so \: p(0) + p(2) = 2 + 0 \\ = 2$